I have thought a bit more about the magnitude of the force due to the acceleration a of a first charge q1 at the retarded time, when it moved at the speed u, on a second charge q2 moving at v. In particular, the speed c in the equation for the moving plane S1 from my previous post seemed suspect to me:
Why should the plane be moving at c rather than a different, modified speed? I tried the speed
This is in fact the speed of the effect of q1
on q2 for the case of charges
moving at uniform velocities. What would happen if I used this speed rather
than just c? The equation for fa< times fa>
(see my previous
post) then becomes somewhat similar to the classical result.
To be more precise, here is an overview of the two results – classical and my own – for part of the magnitude of the vector describing the force, given separately for a212, 2a21a3 and a32 (see the first post on explaining the forces between accelerated charges):
The differences between the classical
solution and my own solution are small for speeds of u and v
smaller than, say, 0.01c. If we set, for example, u = v = 0.01c
and γ = 90°, δ = 30° and θ
= 45°, we obtain for the classical solution, rounded to the fourth digit:
0.9860a212 – 0.0001a21a3 + 0.9859a32
For my own solution, we get a rather
similar result:
0.9859a212 – 0.0001a21a3 + 0.9859a32
If the speed of u and v is
0.9c, on the other hand, we obtain for the classical result:
1.1843a212 – 1.6482a21a3 + 1.1442a32
And for my own solution:
0.5861a212 – 0.5987a21a3 + 0.7125a32
There are thus some real differences,
which I have yet to resolve. I think I will have to consult the literature to
see to what extent the classical solution has been confirmed experimentally.
Next, however, I will present my explanation of the factor outside the square
root term in the classical equation for the magnitude of the force applied by q1 on q2, which is a lot easier to explain than what
I have attempted here over the last four blog posts.
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