Having provided a
new explanation for the forces between charges moving at constant velocity,
I thought that perhaps somebody else would take up the case of accelerated
charges. But it seems that has not happened. So, I have had a go.
I have been working on the magnitude of the force due to the
acceleration a of a first charge q1 at the retarded
time, when it moved at the speed u, on a second charge q2
moving at v. The retarded time is the present time minus the time it
took for the effect of a and u to arrive at q2.
I have not used the concept of the magnetic field as it is
an unexplained (and I would say unphysical) entity in classical physics, nor
have I used the assumption of a uniform two-way speed of light in any inertial frame
of reference made in special relativity, which also calls for an explanation.
I have tried to construct the magnitude of the force on q2
as measured in the frame moving at v. This is because that is the only
force which is unambiguously well defined. The direction of the force, on the
other hand, can be given in the coordinate system in which q2
moves at v. This is assumed to be a coordinate system in which electric conditions
around charges at rest are the same in every direction.
Let me now first consider the classical result. To begin
with, look at this image:
The position of q1 in this image is the
position where q1 was when a signal was sent out from it at
speed c to reach q2 at the present time. The position
of q1* in this image is the position where q1
would be at the present time if it had continued at the constant velocity u
which it had at the time when it had the acceleration [a]. Without loss
of generality, the position of q1* is in the xy-plane.
The vector n is the unit vector in the direction from q1
at the retarded time to q2 at the present time. The green
circle is the circle around the position of q1 that goes
through q2 and the straight line through q1
and q1*.
It is necessary to consider a coordinate system like the one
shown to make the relativistic transformation into the frame moving at v
as simple as possible. In addition to the angles shown, we can define an angle α
as α:
= (
). Then, as per my article on the case of charges moving at constant velocities (copyright: Physics Essays Publications), plus
associated calculations, the following relations apply:
and
It is thus clear that the only independent angles in this
diagram are the angles γ, δ, and θ. We can define the acceleration at the retarded time as:
Remembering that
and
and if we define
and
then the classical formula for the force
on q2, resulting from the acceleration of q1
in the frame of reference shown in the figure, gives us (see for example Rosser,
1997):
Classically, the force on q2 resulting
from the acceleration of q1 as measured in the rest frame of q2,
in other words taking account of electric and magnetic fields and the transformations
of special relativity, is as follows:
As I said before, I have chosen this quite lengthy
coordinate formulation because it is the only way in which I can hope to deduce
the force from first principles. Let me now consider the strength of the force.
The magnitude of the vector sum is the square root of the following term:
I have marked some terms in red: they are what I have calculated so far, with a method similar to the one I used for uniform velocities, as a partial solution for the force due to the acceleration of q1. I do not think it can just be a coincidence that my partial solution yields a subset of the terms of the classical solution. But before I consider this further, I should set out the method used to arrive at my partial solution. In the next few posts.
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